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I converted my bin file to hex file with "bin2ahex". The hex file look like this:
:020000020000fc :040000004d3131410c :0400010000000001fa :040002004ae6a6958f :040003000001e6848e :04000400508b5005c8 :0400050000000000f7 ... :0406c5001e100440bf :0406c600b410000468 :0406c700040100002a :00000001FF Now i want to write this file into my flash EPCS64 at address 0x600000. I use the Convert-Programming-Files in Quartus-II (9.0 SP2). I convert from inputs to a JIC-File. I want to flash the sof (with fpga-configuration + boot-loader) and on a fix flash-address (0x600000) my application. My problem is the error-message "data in hex file overlaps between data blocks at address 1 and address 0". But there is only one data block in the hexfile. I don't understand this message. Can anyone help me?Link Copied
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